10 дек. 2020 г. · In the given example, a = x and b = 3. ∴ ( x + 3 ) 3 = ( x ) 3 + 3 × x 2 × 3 + 3 × x × ( 3 ) 2 + ( 3 ) 3 . |
21 июн. 2023 г. · Therefore, the expanded form of (x + 3)³ is x³ + 9x² + 27x + 27. Explore all similar answers. |
12 мар. 2021 г. · Answer: (x-3)³ = x3 - 9x2 + 27x - 27. Step-by-step explanation: (x-3)³. = (x-3)(x-3)(x-3)³. = x3 - 9x2 + 27x - 27. #CarryOnLearning. |
Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n=n∑k=0nCk⋅(an−kbk) ( a + b ) n = ∑ k = 0 n n C k ⋅ ( a n - k b k ) ... |
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19 янв. 2024 г. · To expand (2+x)3 ( 2 + x ) 3 in the power of x x , you're gonna need to FOIL that out. (2+x)(2+x)2 ( 2 + x ) ( 2 + x ) 2. (2+x)(22+2(2)(x)+x2) ( ... |
4 янв. 2022 г. · Expand (1/x + y/3)³ - On expanding (1/x - y/3)³ using the algebraic identity we get 1/x³ - y/x² + y²/3x - y³/27. |
Expand (1x+y3)3. Open in App Open_in_app. Solution. appImg. Verified by Toppr. (1x+y3)3. ⇒(1x)3+(y3)3+3(1x)(y3)(1x+y3). ⇒1x3+y327+yx(1x+y3x). ⇒1x3+y327+yx2+y23x ... |
16 нояб. 2019 г. · ( x 3 - 3 x ) 3. (a − b)3 = a3 − 3a2b + 3ab2 − b3. = ( x 3 ) 3 - 3 × ( x 3 ) 2 × ( 3 x ) + 3 × ( x 3 ) × ( 3 x ) 2 - ( 3 ... |
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