(x + 1)3 formula is read as x plus 1 whole cube. Its expansion is expressed as (x + 1)3 = x3 + 3x2 + x + 1. |
Answer: The value of (x - 1)3 is x3 - 3x2 + 3x – 1. Here is a comprehensive expansion to this binomial expression. |
To expand the given expression, we can apply the perfect cube formula for a difference, which is as follows: |
25 июл. 2017 г. · x3−3x2+3x−1. Explanation: note that. (x+a)3=x3+(a+a+a)x2+(a.a+a.a+a.a)x+a3. (x−1)3→a=−1. |
Simplify the exponents for each term of the expansion. Simplify each term. Multiply (x)3 ( x ) 3 by 1 1 . Anything raised to 0 0 is 1 1 . |
Ans. The x plus 1 cube formula is an important algebraic identity. The mathematical expression of this formula is (x+1)3. We express this as (x+1)3 = x3 + 3x2 ... |
10 мая 2024 г. · First start with this, [math](x-1)^3=(x-1)(x-1)(x-1)[/math] Now use FOIL on the first two terms. What is the formula for (1-x)^-3? How do I expand (1+x) ^-3 in series? How to expand the expression (3x-1) ^3 How do you expand (x+y-1) ^3? Другие результаты с сайта www.quora.com |
We know that (x+y)3=x3+y3+3xy(x+y). Here x=x and y=1 we get. (x+1)3=x3+(1)3+3(x)(1)(x+1). =x3+1+3x(x+1). =x3+1+3x2+3x. |
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