$\therefore$ The sum of series 1, 3, 5, 7, 9,…… up to n terms is ${{n}^{2}}$. Note: We can also use the sum of 'n' natural numbers to find the sum of the given ...

6 апр. 2023 г. · Therefore, the sum of the sequence 1+3+5+7+…+99 is 2500.

1 июл. 2017 г. · n=(nth term -first term/d)+1=99–1/2+1=49+1=50. sum of n of odd number starting from 1= n*n(n square)[from the first formula]. =50*50=2500. What is the sum of the numbers 1, 3, 5, 7, and 9? What is the sum of 1-3+5-7+9-…n? How to sequence 1 + 3 + 5 + 7 + 9 + 11 +…+27 What is the sum of 1-3+5-7+9-11+…+n? Другие результаты с сайта www.quora.com

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Опубликовано: 8 дек. 2022 г.

9 янв. 2020 г. · Given series is 1,3,5,7,9,...... Sum is 1+3+5+7+9+...+2n−1. ∑(2n−1)2∑n−n2n(n+1)2−nn2+n−n=n2 ; Q1. Find the sum of ·,....... ; Q2. Find the sum of ...

Therefore, 1+3+5+7+9= $5^{2}$ = $5\times 5$ = 25. So, 25 is our required solution for the first series.

The correct option is C 25 1,3,5,7 and 9 are the first 5 odd natural numbers. So, n = 5. In general, sum of the first n odd natural numbers =n2

7 авг. 2024 г. · Thus, the sum of the series 1−3+5−7+9−11+… up to n terms (where n is even) is: Sn=−n.

7 авг. 2024 г. · To find the sum of the series 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 up to the 15th term, we can use the formula for the sum of an arithmetic series.