1.55740772 |
The result can be shown in multiple forms. Exact Form: 2tan(12) 2 tan ( 1 2 ). Decimal Form: 1.09260497… 1.09260497 … 2tan(12) 2 t a n ( 1 2 ) ... |
9 янв. 2020 г. · Correct option is C. − π 2 + tan − 1 ( − 3 4 ) |
The correct Answer is:A, B, C. Let tan−1(−2)=θ or tanθ=−2 ⇒θ∈(−π/2,0) or 2θ∈(−π,0) cos cos2θ=1−tan2θ1+tan2θ=−35 or −2θ=cos−1(−35)=π−cos−1.35 |
The correct Answer is:A, B, C. Let tan−1(−2)=θ or tanθ=−2 ⇒θ∈(−π/2,0) or 2θ∈(−π,0) cos cos2θ=1−tan2θ1+tan2θ=−35 or −2θ=cos−1(−35)=π−cos−1.35 |
21 дек. 2021 г. · 2 tan^(-1) (-2)` is equal to A. `-cos^(-1) ((-3)/(5))` B. `-pi + cos^(-1).(3)/(5)` C. `-(pi)/(2) + ... -1) (-(3)/(4))` D. `-pi + cot^(-1) ... |
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Show that 2tan−112+tan−117=tan−13117. |
Sin(2tan -1 1/3) = sin{sin^-1[(2/3)/(10/9)]} = sin [sin^-1[3/5]] =3/5 (because sin(sin^-1x) =x ) cos(tan -1 |
The correct option is C (α+β)(α2+β2) α32cosec212(tan−1αβ)+β32sec2(12tan−1βα) =α32sin212(tan−1αβ)+β32cos212(tan−1βα) |
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