Given a signed 32-bit integer x , return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, ...

The task is to take a signed 32-bit integer x and reverse the order of its digits. For example, if the input is 123 , the output should be 321 . If the input is ...

class Solution { public: int reverse(int x) { long ans = 0; while (x != 0) { ans = ans * 10 + x % 10; x /= 10; } return (ans < INT_MIN || ans > INT_MAX) ?

15 февр. 2024 г. · Given a signed 32-bit integer x , return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer ...

21 мая 2023 г. · The code uses a while loop to reverse the integer. The loop continues until x becomes 0, which means all digits have been processed. Inside the ...

26 окт. 2020 г. · This problem is pretty straightforward . To reverse an integer, we only have to make most significant digit as the least significant digit and ...

14 мая 2022 г. · In the first code block, rev is an integer. Thus, it is impossible for it to be greater than Integer.MAX_VALUE - the maximum value for an ...

Продолжительность: 13:12
Опубликовано: 18 авг. 2021 г.

public int reverse(int x) { int result = 0; while (x != 0) { int tail = x % 10; int newResult = result * 10 + tail; if ((newResult - tail) /

12 мар. 2024 г. · Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer ...