18 мар. 2018 г. · Then, Delta y = vot - 1/2 gt^2. This gives 62.5 - 31.25 = 31.25 m. Thus, our answer is 31.25 meters in a time of 2.5 seconds.

21 мар. 2019 г. · Q: An object is thrown vertically upward with an initial velocity of 40m/s. Two seconds later another object is thrown with the same velocity.

25 апр. 2020 г. · The time of flight is given by the formula T = 2v sinx /g where x is angle at which it was thrown and v initial velocity , g acceleration due to gravity.

8 мая 2018 г. · A ball is thrown vertically upward with a velocity of 40 m/s. What is the maximum height and time to return to the thrower?

31 янв. 2018 г. · An object is thrown vertically upward with a velocity of 40m/s. Five seconds later, a second object is projected upward with a velocity of 50m/s.

1 мая 2021 г. · An object is thrown vertically upward with an initial velocity of 40m/s. Two seconds later another object is thrown with the same velocity.

23 авг. 2021 г. · The stone will cover maximum height when its velocity in the upward direction becomes zero. · u=initail velocity=40 · a=acceleration=gravity=-10.

13 окт. 2023 г. · Starting at 40 m/s, it loses 10 m/s of vertical velocity every second. Therefore, it will hit a vertical velocity of 0 after 4 seconds. (a more ...

16 июн. 2022 г. · This question can be answered by using the formula of v^2 – u^2 = 2aS where v = the speed to be calculated, u = 40 m/s ; a = -9.8 m/s^2 and S

25 мая 2020 г. · An object is thrown vertically upwards with a velocity of 40m/s and returns back. What is the maximum height taking g=10m/s? Originally Answered ...