1 мар. 2015 г. · The answer is: 1/2e^(2x+1)+c. Remembering the rule: inte^f(x)*f'(x)dx=e^f(x)+c, than inte^(2x+1)dx=1/2int2e^(2x+1)dx=1/2e^(2x+1)+c.

Продолжительность: 1:30
Опубликовано: 18 авг. 2014 г.

Learn how to find the integral of e^x by finding the anti-derivative of e^x and using the fundamental theorem of calculus, then explore a fascinating ...

27 янв. 2015 г. · How do I find the antiderivative of e2x+1?

25 июн. 2020 г. · Take 2x – 1 = t. So we get. 2 dx = dt. It can be written as ...

Simplify. Use logarithm rules to move 2x−1 2 x - 1 out of the exponent. The natural logarithm of e e is 1 1 . Multiply 2x−1 2 x - 1 by 1 1 .

12 февр. 2023 г. · The antiderivative of e^(2x) is given by: ∫ e^(2x) dx = (1/2)e^(2x) + C. where C ... What is the Integral of e^2x/ 1+e^2x dx? Upvote ·. 98.

Продолжительность: 3:14
Опубликовано: 7 дек. 2020 г.

We know that, ddx(e2x)=2e2x. ⇒e2x=12ddx(e2x). ∴e2x=ddx(12e2x). Therefore, the anti derivative of e2x is 12e2x. ; Q2 · ( ; Q4 · cos ; Q5 · sin ...

Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, ...