Apparent weight of the body immersed in a liquid is given as Mg′=Mg−Vpg. What does Vpg stands for in the above equation?

Apparent weight = Weight of body - Upthrust. Weight of a body is given by = volume×density. Here, V= volume, ρ= density of body and g= acc. due to gravity.

-The apparent weight of a body in a liquid is given by, ${W_{apparent}} = W - {F_b}$ where $W$ is the weight of the body and ${F_b}$ is the force of buoyancy or ...

If the object sinks to the bottom, the apparent weight would be the same as the normal force of the object. For buoyant force, the formula to use is: F = ρVg , ...

The correct option is B. W(1−ρ1ρ). Let V be the volume of the body. So, W=ρVg. Now, buoyant force, B=ρ1Vg. Apparent weight =W−B=(ρ−ρ1)Vg=(1−ρ1ρ)W.

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Опубликовано: 14 нояб. 2017 г.

24 нояб. 2018 г. · So we can say apparent weight is object's mass x g - object's volume x density of water x g. However, taking one step further: when weighing an ... What will the apparent Weight of an object be if its fully ... How to calculate the weight of an object in water Stone weights 6.1 N in air and it's apparent weight ... A block of density 2400kg/m^3 has a volume of 0.20 m ... Другие результаты с сайта www.quora.com

Weight calculated by dividing the volume of the object by the volume of water displaced. Thus, Wt = M*g. Where,. Wt = true Weight.

The formula of Archimedes' Principle is: Fb = ρ x g x V. Here,. Fb = buoyant force; ρ = density of the fluid; V = submerged volume; g = acceleration due ...