14 окт. 2016 г. · For large numbers of different coins, you can appeal to the CLT to get the normal distribution as an approximate distribution of the mean bias.

20 июн. 2014 г. · Around page 70 there is exact results for the sum of two independent beta distributions, around page 70 they find an approximation by assuming ...

14 мар. 2024 г. · I want to use a statistical test to explain the difference between the two groups and not just using the mean. Here's the code for it.

14 нояб. 2019 г. · Show activity on this post. I start with two Beta distributions: BetaA(p;αA,βA)=pαA−1(1−p)βA−1B(αA,βA). BetaB(p;αB,βB)=pαB−1(1−p)βB−1B(αB,βB).

1 авг. 2019 г. · Yes. Mostly. By the property called linearity of expectation, the mean of the sum of random variables is the same as the sum of their individual means.

22 июн. 2011 г. · How can I calculate the α and β parameters for a Beta distribution if I know the mean and variance that I want the distribution to have?

17 июн. 2015 г. · Approximate the distribution of the linear combination of n=20 independent beta-distributed random variables, or would the CLT be accurate enough in this case?

25 окт. 2016 г. · The asymptotic distribution of a sample average of a random sample will be governed by the CLT whenever the variance exists, which does not require that α,β>1.

8 июн. 2023 г. · Could I instead fit two priors, one for goalies playing less than 10 games, another for goalies playing more than 10, and then use a simple ...

15 янв. 2013 г. · The short version is that the Beta distribution can be understood as representing a distribution of probabilities.