3 дек. 2016 г. · Here is how I'd do it var1="Hello" spaces=10 # a dynamic value var2="Wissam" printf "%s%$((${#var1} + spaces))s%s\n" "$var1" "$var2" Why does my shell script choke on whitespace or other special ... Spaces in variable assignments in shell scripts Input variables with spaces? - Unix & Linux Stack Exchange How do I echo a string with multiple spaces in bash "untouched"? Другие результаты с сайта unix.stackexchange.com

28 апр. 2011 г. · My question is: How can I make it work using spaces in the variable? ... Is there a solution for this (other than the previous mentioned)?. How can I use a variable that contains a space? - Stack Overflow bash - Assignment of variables with space after the (=) sign? Unix bash assigning string with spaces to a variable Assign string with space to variable from command line argument Другие результаты с сайта stackoverflow.com

18 июн. 2022 г. · You can use printf "%s\n" "$b" $b to show the quoted expansion being a single string with spaces, and the unquoted expansion getting word-split into two args.

26 нояб. 2021 г. · How do I make Linux bash handle arguments with spaces correctly even if I pass the arguments string using a variable or a pipe (tested, ...

27 окт. 2021 г. · I trying to deal with spaces in directory names. As an example: drive=/mnt/g; export drive mydir="$drive/directory with spaces in name" echo "$mydir"

9 окт. 2017 г. · I'd like to store a directory name with spaces in it. I know how to do deal with spaces in file/directory names interactively, using either quoting or \-based ...

4 июн. 2021 г. · How do I pass a variable with spaces or illegal characters to a command inside a bash script? I have a simple little script that I run on each ...

22 янв. 2022 г. · You have to use single quotes inside double quotes or escape double quotes. Additionally, use && instead of ; to run the next command only if the previous one ...

In particular, no whitespace is allowed between the variable name, the equals sign, and the value. All of these examples would cause Bash to throw an error:

12 мая 2020 г. · The problem is that blank is a separator. The for loop uses the $IFS variable for field separators, which by default is set to the space character.