14 мая 2013 г. · You can use declare to create dynamic variable names: declare "magic_variable_$1=$(ls | tail -1)" and use indirect parameter expansion to access the value.

24 февр. 2017 г. · declare -g will make sure the variable exists outside of the function scope, and "VAR_$1" is used to dynamically create the variable names.

9 авг. 2023 г. · Bash: Dynamically create variables with the variable name based on a filename. This question comes from a desire to reduce some repetition in a ...

5 июн. 2017 г. · I have an array called "loop". For each element in "loop" I want to create an array whose name contains the text of the current element.

9 февр. 2017 г. · I was curious to know how to assign to a variable with another variable in its name. Version of Bash is "GNU bash, version 4.1.2"

6 дек. 2016 г. · I'm trying to do that in order to name several samples in a while loop changing the "j" parameter. Anyone knows how to name a variable like that ...

19 июл. 2021 г. · Because bash doesn't support "arrays in arrays", I'm trying to dynamize variable name when calling arrays. bash version : 4.2.

2 февр. 2022 г. · If your bash is recent enough you can use namerefs: function foo { for (( i = 1; i <= 3; i++ )); do local -n number="n$i" number="$i" done ...

12 апр. 2021 г. · Probably a noob question, but I'm having a particular challenge where I want to dynamically generate variable names based on a value. Eg. If I'd ...

15 мар. 2012 г. · I want to declare a variable, the name of which comes from the value of another variable, and I wrote the following piece of code ... a="bbb" $a=" ...