bash exclude lines from file site:unix.stackexchange.com - Axtarish в Google
4 авг. 2013 г. · I want a bash script that will search the complete list for any lines that are in the partial, if there are, they will be removed from the complete list.
4 дек. 2017 г. · Here's a one-liner user grep: grep -Fxv -f file1.txt file2.txt This command outputs the lines in file1.txt which are not in file2.txt - in the order that they ...
10 мая 2012 г. · There are a few ways to do this. Best would be grep : grep -v 'repeat-info' file.log Other ways: sed '/repeat-info/d' file.log sed -n '/repeat-info/!
26 мар. 2023 г. · I want to remove all lines in a file that begin with the letter "i" and DO NOT end with ".conf". The following is a list example.
26 февр. 2018 г. · The sed expression /NA/d will apply the d command on all lines in the input that matches the regular expression NA . The d command deletes lines ...
29 июл. 2013 г. · You can remove said lines of unwanted text by like so sed -i '/[REGEX]/d' <FILE> Where [REGEX] is a regular expression that matches the unwanted line of text.
17 мая 2021 г. · 2 Answers. Just remove the -x option, the use of that is to match the given regex on the exact whole line instead of partially.
3 окт. 2020 г. · Use nl to number the lines of the file, and then join -v1 will keep only lines without match in the second file, finally cut the line number.
17 авг. 2015 г. · Remove lines from a file depending on lines found in another file ... #!/bin/bash cut -d, -f1 file2 | while read key ; do #check for ...
6 июл. 2022 г. · To match using both the first and second fields, create a new combined first field from these in both files and join on this field, then remove the temporary ...
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