bash get variable by name site:unix.stackexchange.com - Axtarish в Google
12 мая 2014 г. · I need to reference environment variables and in one case, I want 2 variables to have the same value. So I need to be able to say "USER1 = $ ...
11 авг. 2015 г. · Then you access it with ${!<varable name>} where <variable name> is a variable holding the name of the variable you want to access.
28 дек. 2015 г. · Different shells have different syntax for achieving this. In bash, you use variable indirection: printf '%s\n' "${!env_name}"
11 мар. 2021 г. · I want to retrieve array values, GNU bash 5.1.0. The array name shall be a variable. "Just" referencing a variable in bash.
11 окт. 2017 г. · If you have bash v4.4 or later you can use ${VAR@A} Parameter expansion operator. This is discussed in the Bash manual under section 3.5.3.
16 мар. 2016 г. · Bash uses the value of the variable formed from the rest of parameter as the name of the variable; this variable is then expanded and that value is used in the ...
10 мар. 2017 г. · I want to write function (let's call it superEcho) that takes a variable name as input. The function should print that variable's name and its value.
22 авг. 2018 г. · Here are some examples: declare [-g] "${foo}=example2" declare -n foo='example1' foo='example2' eval "${foo}=example2"
7 янв. 2013 г. · Bash uses the value of the variable formed from the rest of parameter as the name of the variable; this variable is then expanded and that value ...
23 дек. 2020 г. · A nameref is commonly used within shell functions to refer to a variable whose name is passed as an argument to the function.
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