21 окт. 2018 г. · You need echo "$output" | grep -q "Correct" if all you have is a string variable without a corresponding file.

12 сент. 2014 г. · To assign the output of a command to a variable, use $() : revNumber=$(echo "filename.txt.123" | egrep -o "\.[0-9]+$" | egrep -o "[0-9]+")

9 окт. 2020 г. · You need nullglob to handle the case where the glob doesn't match any files. Without nullglob , you'd end up with NUM_BACKUPS set to 1 if you ...

9 апр. 2011 г. · grep "$(date | awk '{print "2006-" $6}')" /some/file/here "..." holds its contents as one argument (even if there's whitespace). $(...) is for command substitution.

2 мая 2014 г. · It's possible. Try this: grep 'hello' <<< 'hello world' You can also pass a variable containing string instead: str='hello world' grep 'hello' <<< $str

6 авг. 2013 г. · Like this: check=$(sudo virsh list | egrep -c '\b[0-9]{2}\b') $(command) behaves like a variable where the value is the output of command.

27 июн. 2015 г. · Piping output of a command to a variable.. A simple example a bit like yours $ a=$(echo abc | grep -o a) $ echo $a a. So in your case

14 сент. 2012 г. · I'm running this grep command which works as it should but how do I store the returned value into a variable?

3 мая 2011 г. · I am trying to get the number of occurrences in a script and when running the command on the command line, it works fine, but not in a script.

17 мар. 2018 г. · I am testing, whether a new string is in the array - piping the array contents as lines to grep and checking exit code. But it somehow does not work.