10 сент. 2017 г. · Simply running echo $messages would be equivalent to echo ${messages[0]} , giving you only the first array element. Capture multiline output as array in bash - Stack Overflow Bash splitting a multi line string by a multi-character delimiter ... Другие результаты с сайта stackoverflow.com |
Bash shell has syntax for arrays, values should be separated by space and wrapped with round brackets. |
27 мар. 2020 г. · The script looks in /etc/hosts.d/ and creates a list of available files to insert into /etc/hosts and replace the old content between two markers. |
23 апр. 2018 г. · To do so: when you split your command over multiple lines, end each non-end line with “\” to indicate continuation on the next line – then iterate over it. |
3 февр. 2016 г. · I'd like to split the content into an array, so that each multi-line string is an array element. I tried to use IFS, but that only reads the first line. How to declare an array of items in tcsh that separates on ... bash - Multiline variable with spaces, adding each line to an array How can I create a multidimensional array, or something similar ... Другие результаты с сайта unix.stackexchange.com |
30 нояб. 2017 г. · You need to mask the newline to express that the set command continues on the next line. The \ also needs to be right before the newline, because otherwise it ... |
23 февр. 2009 г. · In a Linux bash script, how would I store each line of output from a command into individual elements in an array? Thanks in advance... Explanation of 'read' behaviour when extracting multi-line ... Multi-line return from grep into an array? - LinuxQuestions.org [SOLVED] grep/sed/awk multi line array - LinuxQuestions.org Bash script - output of command into array. - LinuxQuestions.org Другие результаты с сайта www.linuxquestions.org |
8 окт. 2009 г. · And if you are using this multi-line String variable to write to a file, put the variable around "QUOTES" like echo "${String}" > /tmp/ ... |
21 нояб. 2012 г. · All you should need to do is add a \ (backslash) at the end of each line and it should be good to go. So yours will look like: |
23 янв. 2022 г. · #!/bin/bash declare -a messages=( "Hello" "World" ) echo "${messages[@]}". Add Own solution. Log in, to leave a comment. |
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