23 февр. 2009 г. · In a Linux bash script, how would I store each line of output from a command into individual elements in an array? Thanks in advance...

16 дек. 2020 г. · I was writing a bash script which required parsing some multi-line output from some git commands and while attempting to read lines into an ...

16 дек. 2009 г. · I am using this command to load the output of a command into an array and then examine the results: ldapoutputarray=( (su - dcmbox -c ...

How can I get the array to be broken by line? Thanks Anubis.

14 июн. 2005 г. · I was playing with a bash script earlier, that cat'd a file and grep'd it for something like "A|B". This returned a multiple number of lines ...

23 февр. 2012 г. · I want to loop over each block, after which I'll know how to loop over each line in a block ("while read line"), then extract data I need and ...

13 авг. 2012 г. · I want to do an ls -c1 from within a bash script, and output the result with one line per entry. The command below returns a single very ...

5 окт. 2012 г. · The intended goal is to get every variable which has the data in an array converted into a string shell variable. On that note my example ...

24 нояб. 2011 г. · To give line of text its own array element, you can use the new (bash v4+) mapfile command. a.k.a. readarray. Code: mapfile -t LINE < filename # ...

11 мар. 2011 г. · I used grep to grab each individual entry. the -A 12 option means that grep will output the matching string you give it, plus the 12 lines following it.