bash pass arguments to command site:stackoverflow.com - Axtarish в Google
28 янв. 2011 г. · I am writing a very simple script that calls another script, and I need to propagate the parameters from my current script to the script I am executing.
28 сент. 2010 г. · If you want to pass all but the first arguments, you can first use shift to "consume" the first argument and then pass "$@" to pass the remaining arguments to ...
2 июн. 2011 г. · I am trying to search how to pass parameters in a Bash function, but what comes up is always how to pass parameter from the command line.
1 апр. 2013 г. · First big problem: $($2) $line executes $2 by itself as a command, then tries to run its output (if any) as another command with $line as an ...
18 янв. 2013 г. · I have a bash script that employs the read command to read arguments to commands interactively, for example yes/no options.
29 мая 2014 г. · I'm trying to write a bash script that takes an environment variable and passes it along to a command.
14 июл. 2017 г. · I am looking for a generic solution, which can handle multiple arguments and string arguments for arbitrary programs called by the bash script.
13 мая 2012 г. · You can use shift. shift is a shell builtin that operates on the positional parameters. Each time you invoke shift, it "shifts" all the positional parameters ...
29 сент. 2016 г. · Create a file test.sh with the following contents: echo "I was given $# argument(s):" printf "%s\n" "$@". and then source it from an ...
25 сент. 2013 г. · You should use an array, which in some sense provides a 2nd level of quoting: ARGS=(-a "arg one" -b "arg two") ./test.sh "${ARGS[@]}".
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