bash quotes inside quotes site:unix.stackexchange.com - Axtarish в Google
8 июн. 2015 г. · You don't need to escape the nested quotes inside. They get parsed properly, surprisingly! DATA="$(cat file.hex | xxd -r | tr -d "$(cat trim.txt)")"
17 сент. 2020 г. · Double quotes do not nest. That's why you escaped the "inner" quotes in your question. You could use one pair of single quotes and one pair of ...
14 июн. 2016 г. · A double-quoted string that starts inside a command substitution will never extend outside of it or vice versa.
23 нояб. 2014 г. · Enclosing characters in double quotes ('"') preserves the literal value of all characters within the quotes, with the exception of '$', '`', '\' ...
10 мая 2024 г. · Generally, to properly quote a variable within single quotes in Bash, use '"$var"' (single quote followed by double quote).
4 мар. 2021 г. · The data you want to insert into the argument sent to curl is a JSON-encoded string encoding a JSON document. This string can be created separately.
16 июн. 2015 г. · You can't expand variables in single quotes. You can end single quotes and start double quotes, though: echo 'visit:"'"$site"'"'.
17 сент. 2020 г. · Once inside a command substitution, the shell begins an entirely new quoting context. That is, double quotes inside the substitution do not match up with ...
30 мая 2020 г. · I am trying to run a command in shell script which demands its argument to be passed in below format which includes double quotes with string.
6 февр. 2017 г. · Bash will add single quotes (in eg the set -x tracing output) when you use \"$ARGUMENT\" because you're making the double quotes part of the argument's value.
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