8 июн. 2015 г. · My man bash says "If the substitution appears within double quotes, word splitting and pathname expansion are not performed on the results." (in ... |
14 июн. 2016 г. · First, bash parse the right hand side of assignment to one long string $( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd ) because double quote ... |
17 сент. 2020 г. · This section of my parser takes any given string and removes single and double quotes from it (except quotes that are escaped and interpreted as ... |
4 мар. 2021 г. · Might be better to compose the string one piece after the other, then hand it over to the shell. And true, why is sh -c needed? – berndbausch. |
10 мая 2024 г. · Generally, to properly quote a variable within single quotes in Bash, use '"$var"' (single quote followed by double quote). |
23 нояб. 2014 г. · The ' single quote character in your echo example gets it literal value (and loses its meaning) as it enclosed in double quotes ( " ). |
16 июн. 2015 г. · So, I am looking for way to print value inside variable while using single quote. bash · shell · quoting · variable-substitution · Share. |
17 сент. 2020 г. · 1 Answer 1 ... What happens is $ in $( in your code is still special. $( ) is the syntax of command substitution. About command substitution, from ... |
6 февр. 2017 г. · Bash does not add single quotes to your string. The single quotes are how it makes the output of the set -x trace visually unambiguous. In ... |
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