21 мар. 2011 г. · An optimal way to read a multiline variable is to set a blank IFS variable and printf the variable in with a trailing newline. |
11 апр. 2016 г. · you need to double-quote $variable when you use it, otherwise the while loop will get only one line of input. See, for example, the difference ... |
20 дек. 2022 г. · You will be able to read your input with the escaped newline: $ read input hello \ > world $ echo "$input" hello world |
24 окт. 2014 г. · Here are a few bash solutions (some of which should also work in other shells, like zsh ). Firstly with the += append operator. |
16 февр. 2023 г. · Is it possible to process a multiline variable in a bash function? Suppose I have a function theone and I pass a multiline variable to it. |
4 дек. 2020 г. · But in bash , for that to work, you'd need to set the lastpipe option ( shopt -s lastpipe , only works for non-interactive shell instances), for ... |
31 мар. 2019 г. · If you insist on having your $MULTILINE variable, then write that to a file and read it from there: tmpfile=$(mktemp) printf '%s\n' "$MULTILINE ... |
11 мая 2020 г. · I'm trying to read two lines into two variables. In Bash I would use something like this: cat << EOF > myfile line1 line2 EOF cat myfile | { ... |
28 февр. 2019 г. · I am working towards writing a bash script that contains a variable with a long string value. When I split the string into multiple lines it is throwing error. |
15 мая 2019 г. · To use a variable containing multiple lines, you need to make parameter expansion split at newline and skip globbing, and depending on your data possibly avoid ... |
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