bash script first argument site:stackoverflow.com - Axtarish в Google
13 мая 2012 г. · You can use shift. shift is a shell builtin that operates on the positional parameters. Each time you invoke shift, it "shifts" all the positional parameters ...
27 сент. 2017 г. · The shell's argument list is just a sequence of strings. There is no way for the first string to be undefined and the second to be defined, ...
29 янв. 2012 г. · I have a simple script where the first argument is reserved for the filename, and all other optional arguments should be passed to other parts of the script.
26 июн. 2011 г. · It is: if [ $# -eq 0 ] then echo "No arguments supplied" fi The $# variable will tell you the number of input arguments the script was passed.
17 февр. 2012 г. · You could use the default-value syntax: somecommand ${1:-foo} The above will, as described in Bash Reference Manual - 3.5.3 Shell Parameter Expansion.
4 окт. 2019 г. · New in bash script, have to write a function to check if the first given parameter is empty. Output error message if it is empty, otherwise success.
22 мая 2016 г. · I'm attempting to see whether the first argument passed to my script is set. I used the instructions found here to create a test: How to check ...
18 янв. 2012 г. · Use the shift command: #!/bin/bash FIRST_ARG="$1" shift for i in "$@"; do echo $i; done; which skips the first argument.
26 нояб. 2018 г. · Inside test.sh, first argument you passed in command line becomes $1, second becomes $2 and so forth. $@ prints all arguments. Indeed, it is ...
14 апр. 2017 г. · You can remove the first argument with a shift: shift #same as: shift 1 bash abc.sh "$@" (In bash, ksh, and zsh, you can also use "${@:2}" without modifying ...
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