25 апр. 2012 г. · I'm trying to redirect command output to a variable: OUTPUT=$(sudo apache2ctl configtest) and then to read it: echo $OUTPUT. When running it the output is the ...

16 сент. 2012 г. · I have a bash script which calls several long-running processes. I want to capture the output of those calls into variables for processing reasons.

24 мая 2017 г. · You need the shell to expand that variable BEFORE invoking zip command. TO do this you can use eval which takes a first pass at expanding ...

6 мар. 2017 г. · I would like to pipe result of find command to shell and to the next command, which output I want to store in a variable so I could display it nicely later.

17 мар. 2023 г. · Is possible to use variable to define the stdout on bash? No, it is not possible. Instead, redirect stdout.

20 янв. 2013 г. · Write a script, using $RANDOM, to write the following output both to a file and to a variable. The following numbers are only to show the format.

6 нояб. 2018 г. · One way in bash is to run the command in single quotes res=`cmd` or embed the command within $() res=$(cmd) Capture both stdout and stderr in Bash.

10 дек. 2012 г. · How to save each of them to separate variables? My use case here is if the return code is nonzero I want to echo stderr and suppress otherwise.

31 мая 2021 г. · How can I redirect the stdout and stderr to a file path stored in a variable? The file path variable itself gets calculated in the {} construct and doesn't ...

10 янв. 2011 г. · In addition to backticks `command` , command substitution can be done with $(command) or "$(command)" , which I find easier to read, ...