11 февр. 2017 г. · I would like to have a bash script that checks if a file has more than # amount of lines but i have not yet got it working right and I'm not so sure on how to ... |
15 июл. 2016 г. · I have a simple script in Bash to read a number in a file and then compare it with a different threshold. The output is this: : integer expression expected |
23 авг. 2021 г. · To convert the number back to a string of 3 characters representing the number with leading zeros replaced, just use printf with the "%03d" conversion ... |
28 апр. 2013 г. · You can "cast" a string to an int in bash by adding 0 NUM="99" NUM=$(($NUM+0)) This works great if you have to deal with NULLs as well. |
8 апр. 2013 г. · Given a string like '2013-04-06', I want to convert it to a integer as we can do in Java.I have no idea how to do this in bash shell.Does anybody know how to ... |
29 июн. 2012 г. · The standard solution: expr $d1 - $d2. You can also do: echo $(( d1 - d2 )). but beware that this will treat 07 as an octal number! |
19 мар. 2019 г. · Bash has no support for floating point arithmetic. If you just care whether the first digit is bigger than 3, you can simply trim any decimals. |
1 окт. 2013 г. · Use the following instead of for i in {1..$Lastday} for i in $(seq 1 ${LASTDAY}) ; do echo $i done. This will work. |
31 янв. 2020 г. · You can use arithmetic expansion: result=$(( $(ls | wc - l) - 1)) or just ignore one of the files result=$(ls | tail -n+2 | wc -l) |
26 сент. 2014 г. · How to convert string to int in bash? · Consider using wc -l < file to get the number directly. So can you do val=$(wc -l < file) . · Works in ... |
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