10 дек. 2012 г. · I want to run a command from a bash script which has single quotes and some other commands inside the single quotes and a variable.

24 мая 2022 г. · Variables don't expand in single quotes, which means that you simply have to ensure that they are not single-quoted.

17 янв. 2014 г. · Variables are expanded in double quoted strings, but not in single quoted strings. $ name=World $ echo "Hello $name" Hello World $ echo 'Hello $name' Hello $ ...

3 сент. 2017 г. · If you put a variable inside single quotes in bash, I does not get evaluated, you should just use: search="$var" if you want the variable to be enclosed by ...

24 июн. 2016 г. · Parameter expansion doesn't happen in single quotes, you will need to expand in double quotes.

30 мар. 2015 г. · You can achieve this by using double quotes around the entire JSON string and escaping the inner double quotes.

22 сент. 2017 г. · A reasonably straightforward solution is to use a bash array to store the four arguments you will want to pass:

10 нояб. 2011 г. · Rather than attempting to expand a variable inside a single quoted string, the typical solution is to concatenate single and double quoted ...

27 июл. 2015 г. · cURL in Bash - Passing Variables Between Single Quotes · 1. Dropping out of single quotes is the only way to get the variables to get expanded.

19 июн. 2018 г. · I have a couple of arguments in my variable. I want to replace each variable with single quotes, separated by a comma.