22 июн. 2012 г. · Indirect variable reference. Modern advanced shells have a method to reference the value of a variable whose name is stored in another variable.

31 янв. 2018 г. · In bash v4 you can use a "nameref" $ foobar_darwin_amd64=pinto $ package=foobar $ declare -n var=${package}_darwin_amd64 $ echo "$var" pinto

11 нояб. 2020 г. · It depends what shell you are using - in bash, you could use indirection like echo "Welcome ${!i} times" - see for example Bash: Echo a variable whose name is ...

3 янв. 2019 г. · I need to use echo $ENV_ACCOUNT in a command which should resolve to 12345678 but it is resolving to DEV_ACCOUNT instead of 12345678.

22 авг. 2014 г. · Bash uses the value of the variable formed from the rest of parameter as the name of the variable; this variable is then expanded and that value ...

22 авг. 2018 г. · If you use declare var inside a function, then var will be local; but if you use declare -g var , then var will be global. Although, according ...

18 февр. 2018 г. · I want to reference a bash variable from a variable without using: echo "${!VARNAME}". Any ideas? Since I want to use the variable on fly and ...

16 мар. 2016 г. · Bash uses the value of the variable formed from the rest of parameter as the name of the variable; this variable is then expanded and that value ...

12 мар. 2019 г. · I am trying to set the variable service to be the value of var1=first/second echo $var1 | cut -d '/' -f 1 var2=$var1 | cut -d '/' -f 1" echo $var2

19 мар. 2021 г. · I need to extract a path that is set within a config file, to use it in a bash script. This is how that path looks like inside said file: DIR = "${HOME}/test/ ...