6 нояб. 2015 г. · Capturing this and capturing by reference are two orthogonal concepts. You can use one, both, or none. It doesn't make sense to capture this by reference.

13 авг. 2015 г. · A lambda is a syntax for creating a class. Capturing a variable means that variable is passed to the constructor for that class.

12 окт. 2016 г. · The lambda function capture [this] in this case, superseds the normal "this" which refers to the calling object as in "this-B"?

1 июл. 2016 г. · Default-capturing [this] both captures the instance pointer and means that name searching within the lambda also includes the class ...

4 мая 2018 г. · As cppreference says: [=] captures all automatic variables used in the body of the lambda by copy and current object by reference if exists.

1 авг. 2022 г. · The argument in the paper is that at this point we had [this] (captures the this pointer) and [*this] (captures the object itself), and [&] (captures the ...

9 окт. 2017 г. · In the C++ Programming Language, Stroustrop says: Members are always captured by reference. That is, [this] implies that members are accessed ...

19 дек. 2022 г. · If I capture the "this"-ptr in a lambda I can call member functions without problems. However, when I instead capture the pointer explicitely (without ...

1 авг. 2022 г. · As for capturing *this (which you have to do explicitly, and always have done), [*this] will pass a copy of the object itself into the lambda.

5 июн. 2016 г. · The variable is captured by value (ie copied) only once, when you define the lambda. It's not "updated" as you may believe.