Here, wavelength λ=6600Å =6600×10−10m. Energy of photon E=hcλ where, h is Planck.s constant and c is velocity of light. So, E=6.63×10−34×3×1086600×10−10

17 июл. 2022 г. · The energy of a photon of wavelength 6600 Angstroms is: 3×10−16 Joule; 3×10−17 Joule; 3×10−18 Joule; 3×10−19 Joule. The energy of a photon ...

Calculate the energy of a photon of wavelength 6600 angstroms. a) 0.3 × 10-19 J b) 3 × 10-19 J c) 30 × 10-19 J d) 300 × 10-19 J View Answer. Answer: b

9 янв. 2020 г. · JS) The energy of a photon in electron volt, whose wavelength is 6600 A is (h = 6.6 x 10 (A) 0.1875 eV (B) 1.875 eV (C) 18.75 eV (D) 198 eV.

Step by step video & image solution for Calculate the energy and momentum of a photon of wavelength 6600 Å by Physics experts to help you in doubts ...

17 февр. 2023 г. · Question: Calculate the energy of a photon of wavelength 6600 angstroms. a) 0.3×10−19 J b) 3×10−19 J c) 30×10−19 J d) 300×10−19 J student ...

10 сент. 2024 г. · To calculate the energy of a photon, we use the equation E=λhc​, where E is the energy, h is Planck's constant (6.626×10−34Js), c is the speed ...

9 авг. 2024 г. · Reflection Calculate the energy of a photon of wavelength 6600 angstroms. C) 30* 10^(-19)J A) 0.3* 10^(-19)J 300* 10^(-19)J D) ...

9 янв. 2020 г. · Answer 4.97 × 10 − 19 J o u l e. Explanation : E = h c λ. E = h c λ = 6.626 × 10 − 34 J s × 3 × 10 8 m / s 400 × 10 − 10 m. E = 4.97 × 10 − 19 J ...

7 сент. 2024 г. · 3Calculate the energy of a photon of wavelength 6600 angstroms. A. 0.3* 10^(-19)J B. 3* 10^(-19)J C. 30* 10^(-19)J D. 300* 10^(-19)J.