14 февр. 2016 г. · It's basically the number of ways you can write 12 as a sum of three integers all greater than or equal to 3, where order matters. |
6 дек. 2011 г. · The Factor Theorem says that if a polynomial p(x) has root r, then x−r divides p(x). Since polynomial with complex coefficients always have exactly the same ... |
14 мая 2016 г. · If f(x)=∑fixi and g(x)=∑gjxj then the coefficient of xn in f(x)g(x) is ∑i+j=nfigj . For example: Take f(x)=3x30+21x+7&g(x)=2x21+27x2+3. |
11 окт. 2016 г. · You are in the correct way to get the desired formula: (m∑i=0aixi)(n∑j=0bjxj)=m+n∑k=0(∑i+j=kaibj)xk. |
20 сент. 2022 г. · The general process for multiplying two polynomials whose coefficients are given as strings of numbers is called convolution of the two strings. |
6 авг. 2014 г. · The sum of the coefficients is just the value of the polynomial in 1, hence if the polynomial is monic with roots in n1,…,nk, ... |
25 февр. 2023 г. · I'm just trying to find the coefficients A,B,C, of the polynomial Ax2+Bx+C given the points (a,b)(c,d)(e,f). It's the same kind of elimination ... |
11 дек. 2020 г. · (P2)n denotes the coefficient on xn of P(x)2. Applying the linked answer, P2=(N∑k=0pkxk)2=N∑k=0N∑j=0pkxkpjxj. The xk⋅xj can be combined as ... |
11 февр. 2019 г. · Your unique polynomial will have to be of degree at most n, so assume we have p(x)=a0+a1x++…+anxn=n∑k=1akxk. |
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