18 мар. 2019 г. · complete.cases() shows the documentation and gives you all the information you need: It returns a logical vector which specifies which rows have no missing ...

12 мар. 2014 г. · Is it possible to filter a data.frame for complete cases using dplyr? complete.cases with a list of all variables works, of course.

17 июл. 2022 г. · In this example I need to drop all rows with NA values, I tried drop <- is.na(df[,c(3,4,5)]) Error in df[, c(3, 4, 5)] : incorrect number of dimensions.

17 июл. 2018 г. · We can subset the data and apply complete.cases x[complete.cases(x[3:9]),] or using column names x[complete.cases(x[paste0("DC", 3:9)]),]

12 сент. 2012 г. · You can try complete.cases too which will return a logical vector which allow to subset the data by Shoulders

25 июл. 2013 г. · complete.cases checks row-wise for NA, and if present returns FALSE. It's more useful on a data.frame as !is.na(a) would return back a matrix of the same ...

22 июл. 2020 г. · Use complete.cases on just the columns of interest, but use its return value (a vector of logical ) on the original frame.

16 апр. 2019 г. · Is there a function in an existing package which will give the number of missing elements (i.e. NA 's) and number of complete elements for each ...

30 июл. 2019 г. · I have created a function called complete_cases to provide indexes of rows which met the following condition: all columns in the row are NaN.

14 нояб. 2018 г. · You can use dplyr for this. First group_by your grouping variable(s), and then use filter_at to filter on the variables that you care about complete cases for.