cos(1/x) continuous at 0 - Axtarish в Google
7 авг. 2024 г. · The correct Answer is:discontinuous. To discuss the continuity of the function f(x) defined as: f(x)={cos(1x)if x≠01if x=0.
Продолжительность: 3:56
Опубликовано: 16 дек. 2020 г.
Prove cos(x1​) is continuous on (0,1) but not uniformly continuous on (0,1).
Show that the function f(x) defined as f(x)=xcos1x,x≠0, =0,x=0 is continuous at x=0 but not differentiable at x=0.
7 авг. 2024 г. · Summary: The function f(x) is continuous at x=0 because the limit of f(x) as x approaches 0 equals the value of the function at that point.
Продолжительность: 2:29
Опубликовано: 2 февр. 2022 г.
If f(x)={xacos(1/x),ifx≠00,ifx=0 is continuous at x=0 then. α<0; α>0; α=0; α≥0. A. α>0. B. α<0. C. α≥0. D. α=0. Open in App Open_in_app. Solution.
19 апр. 2021 г. · If f(x) = begincases xk cos (1 / x) x ≠ 0 [2ex] 0 x =0 endcases is continuous at x = 0, then (A) k < 0 (B) k > 0 (C) k = 0 (D) k t 0.
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