Need to remember that:sin2(x)+cos2(x)=1 (eq.1)Divide the whole eq.1 by sin2(x)to get:sin2(x)/sin2x+cos2(x)/sin2(x)=1 /sin2x Which is the same ...

cosec(2x) + cot(2x) CONVERT ALL COSEC/COT/SEC FUNCTIONS INTO FUNCTIONS USING ... a) COS(2X) = 2COS2(X) - 1. b) SIN(2X) = 2SIN(X)COS(X). = [1+2cos2(x)-1] ...

Given that 4(cosec x)^2 - (cot x)^2 = k, express sec x in terms of k. This question makes good use of the trigonometric identities tan2x + 1 = sec2x and 1 + cot ...

By forming and solving a quadratic equation, solve the equation 5*cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2*pi, giving the values of x in ...

Since there is no constant term, we can factorise the quadratic by taking out a factor of cot(x), leaving:cot(x)*(cot(x) – 2) = 0.By the factor theorem, the ...

To do this add 11 cot (x) and subtract 16 to/from both sides of the equation in the question. This gives 10 cosec^2(x) + 11 cot(x) - 16 = 0 which can be written ...

Cosec2A - cot2A= tanALeft hand side=1/sin2A - cos2A/sin2A=(1- cos2A)/sin2A=(1-(1- 2 sin^2⁡ A)/ 2sinAcosA=(1-1 + ( 2 sin^2⁡ A))/ ...

For this we have to use trignometric identities, e.g Tan(x)= sin(x)/cos(x), sin2(x) + cos2(x) = 1, 1/sin(x) = cosec(x) tan(x) + cot(x) = sin(x)/cos(x) + ...

2 Secx = 2/CosxCotx = 1/Tan x = Cosx/SinxTherefore: 2SecCotx = 2/Cosx * Cosx/Sinx = 2/Sinx = 2Cosecx. Ben S. avatar. Answered by Ben S. • Maths tutor.

An example of this would be in remembering the trigonometric identity '1+cot(^2)x=cosec ... cot is self explanatory, and 'cosy' refers to cosec. One more thing to ...