The derivative of cot inverse x is equal to d(cot - 1 x)/dx = -1/(1 + x 2 ) . We can derive the cot inverse derivative using the implicit differentiation and first principle of derivatives.
Hence, the derivative of c o t - 1 x is " - 1 1 + x 2 " . |
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What is the derivative of cot^-1(x)? - Socratic socratic.org › questions › what-is-the-derivative...
9 июн. 2018 г. · dydx=−1x2+1. Explanation: Let y=arot(x) then cot(y)=x so. −csc2(y)dydx=1 dydx=−1csc2(x). |
24 сент. 2014 г. · By Implicit Differentiation, f'(x)=-1/{1+x^2} Let us look at some details. By replacing f(x) by y, y=cot^{-1}x by rewriting in terms of ... |
Differentiate using the chain rule, which states that ddx[f(g(x))] d d x [ f ( g ( x ) ) ] is f'(g(x))g'(x) f ′ ( g ( x ) ) g ′ ( x ) where f(x)=cot(x) f ( x ) ... |
16 окт. 2020 г. · Tanuja Let y = cot^-1 x Then by the definition x = cot y Differentiating w.r.t. y we get dx/dy = - cosec^2 y => dy/dx = - 1/cosec^2 y ... |
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