How to Prove the Derivative of Cot x Formula? Let y = cot x. We have cot x = sin x/cos x. By quotient rule, y' = [ sin x · d/dx (cos x) - cos x · d/dx (sin x)] / (sin 2 x) = [-sin 2 x - cos 2 x] / (sin 2 x) = -1 / (sin 2 x) = -csc 2 x .
22 июл. 2016 г. · f'(x)=−csc2x . Explanation: f(x)=cotx=cosxsinx. ∴f'(x)=ddx(cosxsinx)=sinx(ddxcosx)−cosxddx(sinx)(sinx)2. |
Videolar The derivative of cot(x) is -csc^2(x). To find the derivative of cot(x), we can use the quotient rule. Recall that cot(x) = cos(x)/sin(x). Therefore, |
Step 1: Apply quotient rule of differentiation. We know that cot x = cos x sin x applying the quotient rule of differentiation. |
15 мая 2023 г. · The derivative of cot(x) is given by the formula d/dx(cot(x)) = -csc^2(x), where "csc" stands for cosecant. |
26 июл. 2024 г. · Derivative of Cot x is -cosec 2 x. It refers to the process of finding the change in the sine function with respect to the independent variable. |
This can be simplified as -1/sin2x = -cosec2x. So, (d/dx)cot x = -cosec2x. Derivative using Quotient Rule. We can write ... |
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