25 дек. 2018 г. · Usually, the term impulse means the difference in momentum: →J=Δ→p. Force is the time derivative of momentum: →F=d→pdt⇔d→p=→Fdt.

7 февр. 2019 г. · The issue is that your ˙Ek is a derivative with respect to time, t. ˙U≠−F! F=−∇U, which is a spatial derivative, so by the chain rule:.

3 февр. 2016 г. · This is because P(t) as stated is the instantaneous power as a function of time and W=FΔx holds only for constant forces.

17 янв. 2016 г. · The derivative with respect to proper time is the derivative with respect to time of the instantaneously comoving inertial frame.

24 янв. 2015 г. · In other words, if you differentiate energy with respect to time, you get Power (as you have derived in your question - m×a×v would equal F×v, ...

10 июн. 2014 г. · The derivative of momentum just gives us the "regular force" since b4 that momentum = force as a function of time. NOT SURE IF THIS PART IS ...

25 сент. 2021 г. · Suppose we have a force which is dependent on distance from some point. It is easy to find the acceleration based on the distance from that point.

24 янв. 2013 г. · For example if the force on a particle is of the form F=F(r,˙r,¨r,⃛r), then the equation of motion would be a third order differential equation, ...

20 февр. 2020 г. · To add to this, the four-force is given as fμ=dpμ/dτ where dτ is the proper time (of the object's worldline) given as dτ2=−ds2/c2. The integral ...

22 июл. 2014 г. · Finally, in my MCRF, dτ=dt, so you'd get the original force law. Is this a correct way to derive the force law in special relativity? homework- ...