31 мая 2022 г. · Let the volume be V. V = 4/3 (π) r³. To find the rate of change of volume with time, we will differentiate above equation with respect to time.

9 июл. 2016 г. · If both r and h are differentiable functions with respect to time t , then by using the chain rule we have: dV/dt=2(pi)(r)(dr/dt)(h)+(pi)(r ...

21 апр. 2013 г. · The derivative (with respect to the radius) of the volume of a sphere is 4*pi*r² which is equal to the area of that sphere. Indeed, when you ...

8 июл. 2023 г. · V = (4/3) * pi * R^3, and therefore dV/dt = (dV/dR)*(dR/dt) = 4 * pi * R^2 * dR/dt, and d2V/dt2 = 8 * pi * R * (dR/dt)^2 + 4 * pi * R^2 ...

16 сент. 2020 г. · The derivative (with respect to the radius) of the volume of a sphere is 4*pi*r² which is equal to the area of that sphere. Indeed, when you ...

14 июн. 2017 г. · I agree that dV/dS = r/2. Is is worth mentioning that the instantaneous change in volume is equal to the surface area at that instant times the ...

24 окт. 2020 г. · The formula for the volume of the sphere, given the radius is: V = 43π∙r3 V = 4 3 π • r 3 . The derivative of volume with respect to radius is ...

2 мар. 2018 г. · The derivative (with respect to the radius) of the volume of a sphere is 4*pi*r² which is equal to the area of that sphere. Indeed, when you ...

13 окт. 2018 г. · dv/dt = 4πr²*5 in./min. The instantaneous rate of change of volume with respect to time is 20πr².

30 апр. 2016 г. · The volume of each cone is one third of the area of the base times the height. Add them and you have one third of the surface area of the sphere ...