5 окт. 2009 г. · DISTINCT COUNT(*) will return a row for each unique count. What you want is COUNT(DISTINCT <expression>) : evaluates expression for each row in a group.

4 апр. 2020 г. · I am trying to get the best join query to obtain a count with a WHERE clause. I need the count of distinct created_by s from table A with an org_name in Table ...

22 сент. 2022 г. · Use "SELECT DISTINCT ResultCategory, SUM(ResultValue) OVER(PARTITION BY ResultCategory) AS SumResultValue, COUNT(PatientID) OVER (PARTITION BY ...

10 июл. 2020 г. · I want to count the number of distinct names as "name count" where the last date's status is not null and group them by status.

30 авг. 2019 г. · Trying to get an overall distinct count of the employees for a range of records which has a group by on it. I've tried using the "over()" clause but couldn't ...

1 дек. 2009 г. · COUNT(*) is the number of rows matching a query. A row contains unique information such as rowid. All rows are by definition distinct. You must ...

21 июн. 2018 г. · I am expecting the same distinct count in both the results but I get total count as 6147 in first result and 6359 in second result. What is wrong here?

14 июл. 2017 г. · While query select distinct count(a) will give you list of unique counts of values in a. Without grouping it will be just one line with total ...

3 мар. 2017 г. · Try this : select name,count(name) as count from ( select 'ADIESTY.SW' as Name,'2017-03-01' as date union select 'ADIESTY.SW' as Name,'2017-03-02'as date union

28 июл. 2020 г. · Method 1 (returns correct count): SELECT COUNT(DISTINCT contact_id) FROM Traffic_Action WHERE action_type IN ('Schedule a Tour', 'Schedule Follow-up', 'Lost')