17 мар. 2017 г. · In other words, the decimal expansion of π can repeat itself; it just can't ever fall into a cycle where it repeats the same thing forever.

21 мар. 2015 г. · If there are infinite digits in π and any group of digits occurs in π. Then does all the digits of pi occur in itself infinite times over? Therefore π repeats.

17 янв. 2012 г. · As π has infinite digits in its decimal expansion, one could argue that its digits will repeat after a finite number of digits. If so, it is a rational number.

31 янв. 2021 г. · Running an experiment to see how many times different integers of different lengths repeat themselves in the first million digits of pi.

22 окт. 2020 г. · There is no repetition. Your logic (and use of the PHP) works for long division with integers. It doesn't apply to π because π is irrational: ...

18 окт. 2012 г. · This property does not follow from the fact that the decimal expansion of π is infinite and does not repeat. The one more thing is the ...

28 окт. 2015 г. · I was wondering at which decimal place π first repeats itself exactly once. So if π went 3.143141592..., it would be the thousandth place, where the second 3 is.

11 янв. 2016 г. · By definition, every sequence is a subsequence of itself. So yes, the set of digits of π contains itself.

20 июл. 2023 г. · So, the conclusion would be: assuming that digits of π can be treated as random digits, and knowing that the repetition does not happen within ...

1 окт. 2015 г. · If π contains itself as a subsequence then the digits of π repeat themselves, which implies that π is rational. π is irrational, so this doesn't happen.