19 июн. 2010 г. · Question asks whether some number k has a factor p which is more than 1 but less than k. For example if k=10 then the answer is yes.

8 сент. 2010 г. · We can prove that 15! + 1 is not divisible by any numbers between 2 and 15. It's largest prime factor must then be 17 or greater.

13 июн. 2019 г. · Since K must be less than/equal to M, A^K will always be a factor of B^M and the answer to the question is ALWAYS YES. Combined, SUFFICIENT.

23 апр. 2016 г. · stonecold wrote: If a positive integer is given by where is a prime number greater than 2,how many even divisors does n have ? A)4. B)3. C)2. D) ...

12 мая 2011 г. · The answer is B: 17! + 2 <= Z <= 17! + 17 means that z is like 17! + 2, 17! + 3 etc. So you can factor out a common integer from the expressions that will ... Не найдено: ≤

18 нояб. 2012 г. · It is now easy to verify that is sufficient, since p = q = k = 1 gives , but if p = q = 1 and k = 2 then a = 4, b = 4, and the product is 16, ...

11 мая 2020 г. · Since we have many variables to determine a function, E is most likely the answer. So, we should consider conditions 1) & 2) together first.

9 июн. 2016 г. · [GMAT math practice question] If n is a positive integer, is 91 a factor of n? 1) 91 is a factor of n^2 2) 91 is a factor of 2n

20 окт. 2022 г. · If 15 is a factor of p as well as q, is 15 the highest common factor of p & q? 1. q=3p. 2. q-2p=15. Source: Expert's Global | Difficulty: Medium

28 дек. 2009 г. · The answer would be the number which contains all the factors of the figure. The series of 1 to 11 contained all the factors of 990. 2,3,3,5 and 11.