27 авг. 2015 г. · When you refer to a variable without quotes around it (eg echo $files ), the shell splits the value apart on whitespace and passes each term as a separate ...

28 янв. 2016 г. · Use single quotes around variables to prevent shell expansion. Example echo '$file' will not expand $file . Edit after comment below ...

16 июн. 2017 г. · To get the ith / -delimited field using awk, set an awk variable, var for example, to the value of $i, then use $var in awk to access the ith field.

21 апр. 2022 г. · It is to do with scope. By default all variables are global in scope and can be written to and read from both within and without functions.

19 июн. 2017 г. · I want to echo the $i variable name, not its content. The echo output should be "test1", or "test2", or "test3" How can I do this?

24 февр. 2021 г. · How to pass the variable value in echo statement? testvar="actualvalue" echo 'testing "${testvar}", "testing", "testing" ; ...

14 февр. 2022 г. · Why echo is printing string variables before additional text that have been merged with it? · You're using $data as if it is an array, but it's ...

16 окт. 2017 г. · I'm trying to make a bash script that needs to find http://0.0.0.0:3468/* in a bunch of logs in /opt/plex/*.log, display it at the terminal for the user and at ...

12 мая 2014 г. · The answer to this question from SO says to use echo ${!var}, but when I do that I echo just returns a blank line.

24 окт. 2014 г. · Quoting a variable will also be helpful while passing arguments to commands. In the below command, echo only gets single argument as "Hello ...