Therefore the equivalent weight is =M6. In acidic medium potassium dichromatic acts as an oxidant according to the equation, Cr2O2−7+14H++6e−→2Cr3++7H2O.

Equivalent weight = molecular weight / X factor. = 294 6 = 49. Hence, the equivalent weight of potassium dichromate in an acidic medium is 49 g/eq.

The correct answer is 49. Key Points In the solution, K2Cr2O7 gives the following ions, K2Cr2O7 + 14H+ + 6e– → 2K+.

The equivalent mass of K2Cr2O7=Formula mass of K2Cr2O7 Total change in the oxidation number of Cr=2946=49.

Assertion :- In acidic medium, equivalent weight of K2Cr2O7 is equal to 294/6. · In acidic medium, the equivalent weight of KMnO4 will be · Equivalent weight of H ...

The chemical equivalent is 6 because six electrons participate in the chemical reaction. Step 3: Calculation for equivalent weight: Let's consider “M” be the ...

We will get the final value of equivalent weight = 49 g/mol. Additional information: Potassium dichromate, is a common inorganic chemical reagent, most commonly ...

In K 2 Cr 2 O 7 oxidation state of C r = + 6 . In acidic medium, Cr + 6 ⟶ Cr + 3. Thus, Change of oxidation state of K 2 Cr 2 O 7 = 6 . Equivalent weight of ...

The correct answer is (b) 14H++Cr2O72−+6e−⟶2Cr3++7H2OEq. wt = Mol. wt. No. of electrons gained = Mol. wt. 6.