Thus, we get the equivalent weight = Molecular weight. which is 392.

In Mohr's salt oxidation of Fe2+ to Fe3+ involves only one electron change. ∴ Equivalent weight= Molecular weight1. Molecular weight=392. Was this answer ...

We can easily calculate the molecular weight of Mohr's salt. $Equivalent\,weight=\dfrac{Molecular\,weight\,of\,Mohr\,salt}{Number\,of\,electrons\,gained\,or\, ...

The equivalent weight of Mohr's salt FeSO4. (NH4)2SO4. 6H2O in redox change is equal to its. A. molecular weight/2. B. atomic weight. C. molecular weight/3.

The correct option is B One-fourth of the molar weight. Mohr's salt FeSO4.(NH4)2SO4.6H2O has a molar mass of 392 g/mol. We know that n-factor of salts = total ...

n-factor of Mohr's salt = change in oxidation state of Fe. Thus, n-factor = 1. The equivalent weight is molecular weight divided by the n-factor.

The correct answer is Chemical formula of hydrated Mohr's salt is FeSO4NH42SO4,6H2O Equivalent weight = Molar mass number of electron lost or gained ...

The correct answer is Eq.wt=Mol.wtn 'n' for Mohr's salt in acidic medium =1 Eq.wt=M.wt1=3921=392.

20 окт. 2024 г. · For Mohr salt, each Fe2+ ion loses 1 electron to become Fe3+, so the equivalent weight of Mohr salt is its molecular weight divided by 1.