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4^(8/3) is equal to 16, so the final answer is: (16/(8/3)) = (16 * 3/8) = 6. So, the value of the iterated integral is 6. |
Evaluate the iterated integral by converting to polar coordinates. Integral from 0 to 2 integral from 0 to sqrt(2x - x^2) of sqrt(x^2 + y^2) dy dx ... |
Answer to: Evaluate the iterated integral \int_0^4 \int_0^{y^2} x^2y \,dx\,dy By signing up, you'll get thousands of step-by-step solutions to... |
Evaluate the iterated integral. First do the inner integral (w.r.t. to ... x2y dx dy. Steps. Example. 4. Page 5. 1. By looking at the limits of integration. |
16 янв. 2023 г. · We can evaluate this iterated integral by converting it to polar coordinates. The first integral has an upper bound of a and a lower bound of 0. |
Sol: Let r = (x, y, x + y2), then rx = (1,0,1),ry = (0,1,2y) rx × ry = (−1,−2y,1) and |rx × ry| = p2+4y2. Thus, we have. ZZ. S y dS = Z 1. 0. Z 2. 0. |
23 дек. 2022 г. · The iterated integral by converting to polar coordinates \int_(0)^(a)\int_(-√(a^2-y^2))^(0)7x^2ydxdy is 7a^4/12. |
The inner integral is \( \int_{0}^{\sqrt{x}} \frac{y}{x^2 + 1} \, dy \). Since \(x^2 + 1\) is constant with respect to \(y\), factor it out:\[\frac{1}{x^2 + ... |
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