Given a singly linked list's head. Find the first node of the loop if the linked list has a loop. If a loop is present return the node data of the first ... |
11 сент. 2024 г. · The task is to find the Starting node of the loop in the linked list if there is no loop in the linked list return -1. |
Given the head of a linked list that may contain a cycle, return the starting point of that cycle. If there is no cycle in the linked list return null. |
Given the head of a linked list, return the node where the cycle begins. If there is no cycle, return null . There is a cycle in a linked list if there is ... |
If the inner-loop visits the node next to the outer-loop node, then we have found the starting point of the cycle which is the current node of inner-loop, ... |
//Function to find first node if the linked list has a loop. int findFirstNode(Node* head). {. Node* slow = ... |
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the next pointer. Internally, pos is ... |
Given a linked list, there may exist a single loop or no loop. If there are a total of X elements present in a loop, return X-1 as your answer. |
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