21 июл. 2021 г. · A parabola can have 0, 1, or 2 x-intercepts. This can be found by the determinant in the quadratic formula (sqrt(b^2 - 4ac)). · If b^2 - 4ac > 0, ...

13 нояб. 2018 г. · f(x=0 f ( x = 0 and solve for x x to find x x intercepts. If you get square root of negative number, there are no real x x intercepts.

14 июл. 2020 г. · If you have a linear equation, just set the y-value equal to 0 and solve for x. If you have a quadratic equation, again set the y-value to 0 and ...

28 сент. 2023 г. · In general, to find x intercepts, set your function equal to zero and solve. Many x-intercepts can be found by hand if the function can be ...

5 сент. 2017 г. · If y= ax^2+bx+c, then the number of x-intercepts depends on the value of the discriminant. The discriminant is b^2–4ac. Now, b^2–4ac may be less ...

18 мар. 2022 г. · Depends, maximum possible is given by the highest exponent of x. Example (x-1) has one x-intercept, at x=1. (x+1) has no real root, so no x-intercept.

23 окт. 2020 г. · x-intercept is obtained by putting y = 0. Given eqn is : 5 x - 2 y = 10. Put y = 0. => x = 2.

20 мар. 2018 г. · The highest exponent is 1: no x-intercept or one x-intercept possible. There may be any number of x-intercepts, but only one y-intercept, ...

16 дек. 2020 г. · You can determine the x and y-intercepts by looking at where the graph intersects the x-axis (for x-intercept) and y-axis (for y-intercept).

21 июл. 2021 г. · A parabola can have 2,1 or 0 x-intercepts. If the equation of parabola is given then substitute y=0, and by finding the value of b^2–4ac , we ...