First 8 multiples of 3 are 3, 6, 9 ....... upto 8 terms. We can observe that the above series is an AP with a = 3, d = 6 - 3 = 3, n = 8. Sum of n terms of an ...

9 янв. 2020 г. · Find the sum of first 8 multiples of 3. View Solution.

Sum of terms (Sn​) = ? Hence the sum of the first 8 multiples of 3 is 108. Additional information: Sum of n terms in a sequence can be evaluated only if we ...

29 янв. 2023 г. · First 8 multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24. Sum of all = 3 + 6 + 9 + 12 + 15 + 18 + 21

29 мар. 2018 г. · First 8 multiples of 3 are. 3, 6, 9, 12, 15, 18, 21, 24. The above sequence is an A.P. a= 3, d= 3 and last term l = 24.

First 8 multiples of 33 6 9 12 15 18 21 24S = 3 + 6 + 9 + 12 + 15 + 18 + 21 + 24These numbers are in A.Pwhere a = 3 d = 3 and n = 8s n = n / 2 [2a + n ...

Therefore sum of first 8 multiples of 3 is 108. Tutorialspoint.

As we know that, sum of n terms of an A.P.-. Sn=n2(a+l). S8=82(3+24). S8=4×27=108. Hence, sum of first eight multiples of three is 108.

The sum of three consecutive multiples of 8 is 888. Find the multiples.