10 окт. 2013 г. · On most Linux systems, simply typing whoami on the command line provides the user ID. However, on Solaris, you may have to determine the user ID ... |
26 авг. 2016 г. · Simply use the id command. id username [root@my01 ~]# id sylvain uid=1003(sylvain) gid=1005(sylvain) groups=1005(sylvain) |
25 сент. 2012 г. · Try the -p option of the ps command. For instance, if you have PID 1234, run: ps -u -p 1234. The -u was added to include the username in the output. |
2 июл. 2017 г. · Here is all the info on the current user. Note that because $USER is just a variable, it can be changed whereas the id command gives the ... |
7 мая 2009 г. · On a modern glibc system, use this command: getent passwd "username" | cut -d ':' -f 5 That'll get you the passwd entry of the specified user, independent of ... |
8 июл. 2011 г. · You can use getpwent() to get each successive password entry until you find the one that matches the currently logged in user, then parse the gecos field. |
21 янв. 2012 г. · The function getlogin_r() defined in unistd.h returns the username. See man getlogin_r for more information. Its signature is: |
22 июн. 2021 г. · There is a better way if you want to get the username of the user executing the VM: String username = System.getProperty("user.name"); System.out.println( ... |
2 сент. 2016 г. · You can retrieve the id user with getuid and then call getpwuid_r to find out the username the corresponds to that id. |
15 апр. 2020 г. · To get the name of the user who initiated sudo you can call echo $SUDO_USER. To get its home directory: getent passwd $SUDO_USER | cut -d: -f6. |
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