19 мая 2011 г. · GNU grep has the -P option for perl-style regexes, and the -o option to print only what matches the pattern. |
2 янв. 2012 г. · You can use -o and change the grep a little bit -o, --only-matching Print only the matched (non-empty) parts of a matching line, with each such part on a ... |
14 июн. 2020 г. · Capturing groups are numbered by counting their opening parentheses from left to right. In the expression ((A)(B(C))), for example, there are four such groups. |
7 дек. 2017 г. · I have a output from a command that I want to pipe to some kind of grep command to obtain the part in each line that matches a given regex, and only output the ... |
4 окт. 2013 г. · I would like to print out the match groups. Is there a way to do this without Perl/Python? I tried using sed, but I couldn't manage to make it work. |
17 мар. 2017 г. · Print only the matched (non-empty) parts of a matching line, with each such part on a separate output line. |
7 нояб. 2011 г. · It need a way to match lines to a pattern, but only to return the portion of the line after the match. The portion before and after the match will consistently ... |
29 янв. 2018 г. · I'm trying to print only a matching word that are found through a regular expression. Below, I want all the OPENSSL_NO_* options that are present in the source ... |
28 февр. 2017 г. · Instead of using extended-regex grep ( -E ), use perl-regex grep instead ( -P ), with a lookbehind and lookahead. $ grep -oP "(?<=\[)[0-9]. |
3 июн. 2020 г. · The -o makes grep only print the matched portion of the line and the -P enables Perl compatible regular expressions which give us + and \K . The ... |
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