grep regex group site:stackoverflow.com - Axtarish в Google
22 дек. 2011 г. · I have following string:/_id":"scheme_version","_rev":"4-cad1842a7646b4497066e09c3788e724","scheme_version":1234} and I need to get value of "scheme version",
12 дек. 2009 г. · This uses =~ which is Bash's regex match operator. The results of the match are saved to an array called $BASH_REMATCH.
14 окт. 2019 г. · If you have either pcregrep or pcre2grep you can use the -o1 command-line flag to request that only capture group 1 is output.
30 авг. 2014 г. · Is there a way to specify what regexp group I want to append to my file? In the example below I only want to store (\d{8}) in my file: grep -P1 -o kamilla(\d{8 ...
31 мая 2019 г. · I'm trying to capture 3.4.0.0 from each text file and display on the terminal. the command i've written is this : grep -m1 'Version[\s\S]*?(\d[\s\S]+?)\
16 апр. 2019 г. · The easiest solution is to truncate the match after you matched the text up to the 9th pipe with \K match reset operator.
16 июл. 2014 г. · I wrote a regular exprssion: (?<value>(?<=start=)\d+) I'tested it in Exprsso and it works When Itried to use it in BASH script, there are no result.
19 сент. 2013 г. · I want to extract the value pair from a key-value pair syntax but I can not. Example I tried ... echo employee_id=1234 | sed 's/employee_id=\([0-9] ...
1 июн. 2017 г. · grep does not have the capabilities to print using named captured groups. Using sed with regular captured groups (not named) for your given example,
2 июн. 2018 г. · How to correctly use regex group capture with the grep command? · use PCRE if you have GNU grep.. otherwise, use sed/awk... – Sundeep. Commented ...
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