8 нояб. 2011 г. · To grep a pattern in a specific file, and get the matching lines: grep -n <Pattern> <File> | awk -F: '{ print $1 }' | sort -u or using cut as suggested by @

10 дек. 2014 г. · I would like to use the grep command to print a line number for the string I'm searching for. However, when I used the command grep -n it prints ...

5 сент. 2012 г. · grep -o will print only the matching part of the line. Otherwise grep will print any lines with the pattern.

2 дек. 2016 г. · All of these commands will print any input lines containing at least one number: $ grep '[0-9]' file bar 12 $ grep -P '\d' file bar 12 $ awk ...

13 нояб. 2016 г. · Traditional grep is line-oriented. To do multiline matches, you either need to fool it into slurping the whole file by telling it that your input is null ...

I tried to find only "xyx" word if exist in line and return line number. for example in this input just line 2 and 4 have "xyx" , and the result I desired is ...

29 сент. 2014 г. · You can use cut command for this purpose. grep Path filename |cut -c6- Here -c6- option means print from 6th to last character.

6 авг. 2017 г. · You can find the empty lines, and their line numbers, with grep -E --line-number --with-filename '^$' file.txt. An example:

18 окт. 2020 г. · I want to show all lines before a match, not only 10, or 7, or 14 for example, as explained in How do I fetch lines before/after the grep result in bash?

26 июл. 2013 г. · I would like to know a handy command to search for some strings in multiple plain text files and show the line number where it matchs in the output.