21 мар. 2014 г. · For a normal random variable X, with mean μ and standard deviation σ the probabiliity that it smaller than some value c is: P(X≤c)=F(c;μ,σ) ... |
16 апр. 2014 г. · It suffices to use the standard formula for variance of a binomial variable. Standard Deviation = sqrt(250*0.04*0.96) So about 3 in your case. |
5 авг. 2017 г. · In Minitab 16 you can get P(X≤40) and then subtract from 1. |
7 нояб. 2015 г. · The method to find the percentage p of values above a certain point a in a normally distributed set with the mean μ and standard deviation σ is to integrate ... |
30 окт. 2016 г. · Determine the percentage of workers which lie within ONE standard deviation of the mean? Please help me I don't know what formula to use for ... |
14 июн. 2021 г. · First you need to figure out how many standard deviations 65 is from the mean, then you can use a Z-table or a statistical calculator to see what the ... |
8 апр. 2017 г. · The empirical rule can be broken down into three parts: (1): 68% of data falls within the first standard deviation from the mean; (2): 95% fall within two ... |
5 сент. 2014 г. · Let the weight of the chickens be X. Then X∼N(μ,σ2) where σ=4.2 is the standard deviation of the weights and μ is the mean of the weights. |
12 дек. 2011 г. · So you will need to solve for p as p=μ+14. You should check that plugging this into the standard deviation formula √4p(1−p) gives you something ... |
2 апр. 2014 г. · The area under the curve gives you a percentage (that's how the normal curve works - the entire area is 1 or 100%). The area turns out to be ≈ ... |
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