if k is a positive integer, what is the remainder when (k + 2)(k 3 k is divided by 6) - Axtarish в Google
14 дек. 2017 г. · The product of 4 consecutive integers is always divisible by 4! = 24 and hence by 6. Thus, the remainder when (k + 2)(k^3 – k) is divided by 6 is 0.
18 авг. 2020 г. · If k is a positive integer, what is the remainder when (k + 2)(k^3 – k) is divided by 6 ? A. 0 B. 1 C. 2 D. 3 E. 4.
Hence, when ( k + 2 ) ( k 3 − k ) is divided by 6 the remainder will be 0 . ... If k is a positive integer, what is the remainder of (k + 2)(k^3 - k)/6.
24 янв. 2024 г. · Final Answer. The remainder when (k + 2)(k^3 – k) is divided by 6 is 2k. Key Concept. Polynomial Remainder ...
15 апр. 2022 г. · Answer: remainder of the equation is 2 when divided by 3. Step-by-step explanation: Given :- To find :- remainder when the above equation is divided by 3.
22 июн. 2017 г. · The remainder will be 1. By the 1st condition k will be equal to 7x+6 so that remainder will be 6. Wen 2 is added to it the remainder will be 1 ...
Продолжительность: 3:17
Опубликовано: 17 окт. 2022 г.
28 нояб. 2018 г. · If k is a positive integer, what is the remainder when (k + 2)({k}^{3} – k) is divided by 6 ? A0. B1. C2. D3. E4.
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